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7.9x^2+4.6x-5.8=0
a = 7.9; b = 4.6; c = -5.8;
Δ = b2-4ac
Δ = 4.62-4·7.9·(-5.8)
Δ = 204.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.6)-\sqrt{204.44}}{2*7.9}=\frac{-4.6-\sqrt{204.44}}{15.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.6)+\sqrt{204.44}}{2*7.9}=\frac{-4.6+\sqrt{204.44}}{15.8} $
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